• Engineering Economics Solved Problems Pdf 2017
• Solved Problems Pdf
• Engineering Economics Solved Problems Pdf Online

By solving for A in the uniform series present amount factor. That is, Example Suppose a piece of equipment needed to launch a project must be purchased at a cost of $50,000. The entire cost is to be financed at 13.5% per year and repaid on a monthly installment schedule over four years.

1. 3 Suggestions for solving problems n Lookup unfamiliar terms in the index n Draw cash flow diagrams n Identify P, A, F, i n Be flexible in using equations and tables n Check with alternate methods.
2. Example 4.5 Present Worth of a Sugar Mill 61 Example 4.6 Invest in Gold or Stock Market 62 Example 4.7 Electric/Gas Hybrid Vehicle 63 Example 4.8 Effect of Inflation on PW 64 Example 4.9 Life-Cycle Cost Analysis of HVAC Systems 65 Example 4.10 Municipal Garbage Collection Truck 66 Example 4.11 Hexane Extraction of Rice-Bran Oil 66 4.4 Annual Worth Analysis, AW 67.

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Download MG6863 Engineering Economics (EE) Books Lecture Notes Syllabus Part A 2 marks with answers MG6863 Engineering Economics (EE) Important Part B 16 marks Questions, PDF Books, Question Bank with answers Key, MG6863 Engineering Economics (EE) Syllabus & Anna University MG6863 Engineering Economics (EE) Question Papers Collection.

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MG6863 Engineering Economics (EE) Part A & Part B Important Questions with Answers

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MG6863 Engineering Economics (EE) Syllabus

UNIT I INTRODUCTION TO ECONOMICS

Introduction to Economics- Flow in an economy, Law of supply and demand, Concept of Engineering Economics – Engineering efficiency, Economic efficiency, Scope of engineering economics – Element of costs, Marginal cost, Marginal Revenue, Sunk cost, Opportunity cost, Break-even analysis – V ratio, Elementary economic Analysis – Material selection for product Design selection for a product, Process planning.

UNIT II VALUE ENGINEERING

Make or buy decision, Value engineering – Function, aims, Value engineering procedure. Interest formulae and their applications –Time value of money, Single payment compound amount factor, Single payment present worth factor, Equal payment series sinking fund factor, Equal payment series payment Present worth factor- equal payment series capital recovery factor – Uniform gradient series annual equivalent factor, Effective interest rate, Examples in all the methods.

UNIT III CASH FLOW

Methods of comparison of alternatives – present worth method (Revenue dominated cash flow diagram), Future worth method (Revenue dominated cash flow diagram, cost dominated cash flow diagram), Annual equivalent method (Revenue dominated cash flow diagram, cost dominated cash flow diagram), rate of return method, Examples in all the methods.

UNIT IV REPLACEMENT AND MAINTENANCE ANALYSIS

Replacement and Maintenance analysis – Types of maintenance, types of replacement problem, determination of economic life of an asset, Replacement of an asset with a new asset – capital recovery with return and concept of challenger and defender, Simple probabilistic model for items which fail completely.

UNIT IV DEPRECIATION/fx-5500-driver.html.

Depreciation- Introduction, Straight line method of depreciation, declining balance method of depreciation-Sum of the years digits method of depreciation, sinking fund method of depreciation/ Annuity method of depreciation, service output method of depreciation-Evaluation of public alternatives- introduction, Examples, Inflation adjusted decisions – procedure to adjust inflation, Examples on comparison of alternatives and determination of economic life of asset.

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Engineering Economics Solved Problems Pdf 2017

SOLVING ENGINEERING ECONOMICS PROBLEMS

The techniques presented so far illustrate how to convert single amounts of money, and uniform or gradient series of money, into some equivalent sum at another point in time. These compound interest computations are an essential part of engineering economics problems.

The typical situation is that we have a number of alternatives; the question is, which alternative should we select? The customary method of solution is to express each alternative in some common form and then choose the best, taking both the monetary and intangible factors into account. In most computations an interest rate must be used. It is often called the Minimum Attractive Rate of Return (MARR) to indicate that this is the smallest interest rate, or rate of return, at which one is willing to invest money.

CRITERIA

Solved Problems Pdf

Engineering economics problems inevitably fall into one of three categories:

Engineering Economics Solved Problems Pdf Online

1. Fixed input. The amount of money or other input resources is fixed. Example: A project engineer has a budget of $450,000 to overhaul a plant.

2. Fixed output. There is a fixed task, or other output to be accomplished. Example: A mechanical contractor has been awarded a fixed price contract to air-condition a building.

3. Neither input nor output fixed. This is the general situation where neither the amount of money (or other inputs), nor the amount of benefits (or other outputs) are fixed. Example: A consulting engineering firm has more work available than it can handle. It is considering paying the staff to work..